The base of an isosceles triangle measures 80cm and its are 360cm square . find its perimeter
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let side are a , a , b
a + a + b = 80 cm
2a + b = 80
a^2/2 = 360
a^2 = 720
a^2 = 4*5*36
a = 12√5
b = 80-24√5
Hope it helped you...
a + a + b = 80 cm
2a + b = 80
a^2/2 = 360
a^2 = 720
a^2 = 4*5*36
a = 12√5
b = 80-24√5
Hope it helped you...
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