the base of an isoscles triangle is 4/3cm. the perimeter of the triangle is 4 2/15cm what is the length either of the remaining equal sides
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given ABC IS ISOCELES
SO AB =AC AND BC = 4/3
AB +BC+CA=62/15
2AB+4/3=62/15. (AB=AC)
2AB=62/15-4/3.
2AB =62/15-20/15
2AB=42/15
AB=42/15×2
AB=21/15= 7/5=AC
SO AB =AC AND BC = 4/3
AB +BC+CA=62/15
2AB+4/3=62/15. (AB=AC)
2AB=62/15-4/3.
2AB =62/15-20/15
2AB=42/15
AB=42/15×2
AB=21/15= 7/5=AC
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