The base of an isoselles triangle measures 80 cm and it area in 360 m^2 find the perimeter of the triangle
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Area of isoseles triangle =1/2×b×h=360
=1/2×80×h=360
height =360/40
height=9m
triangle Adc
ac^2=ad^2+dc^2
=(9)^2+(40)^2
=81+1600=1681
ac^2=(41)^2
ac=41m=2ab
perimeter of isoseles triangle=2×equal side+third side
=(2×ac+bc)
=2×41+80=82+80=162m
=1/2×80×h=360
height =360/40
height=9m
triangle Adc
ac^2=ad^2+dc^2
=(9)^2+(40)^2
=81+1600=1681
ac^2=(41)^2
ac=41m=2ab
perimeter of isoseles triangle=2×equal side+third side
=(2×ac+bc)
=2×41+80=82+80=162m
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