the base of an isosles triangle is 18 cm and its area is 108 cm cube . find its perimeter.
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hey buddy here is your answer
Given base = 18 cm
==> Area = 108 cm^3
==> as we know = A = bh/2
==> 108= 18h/2
==> 108= 9h
==>12 cm=h
==> now we need to know other sides by using Pythagoras theorem
==> A^2= B/2^2+ h^2
==> A^2 = 18/2^2 + 12^2
==> A^2 =81+144=225
==> A= 15
now formula for perimeter of isosceles triangle= 2a+b
==> 2*15+18 = 48cm (perimeter)
mark brainliest if you got your answer
Given base = 18 cm
==> Area = 108 cm^3
==> as we know = A = bh/2
==> 108= 18h/2
==> 108= 9h
==>12 cm=h
==> now we need to know other sides by using Pythagoras theorem
==> A^2= B/2^2+ h^2
==> A^2 = 18/2^2 + 12^2
==> A^2 =81+144=225
==> A= 15
now formula for perimeter of isosceles triangle= 2a+b
==> 2*15+18 = 48cm (perimeter)
mark brainliest if you got your answer
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