Question

the base of an traingle is 4cm greater than attitude if it's area is 48 cmsq then find base and attitude​

Answer 1

Let the altitute be x

base is then (x+4)

$\frac{1}{2} x(x+4) = 48\\\\x(x+4) = 96\\\\x^2+4x - 96 = 0\\\\x^2+12x-8x-96 = 0\\\\x(x+12)-8(x+12)=0\\\\(x-8)(x+12) = 0\\\\x -8 = 0 \ \ \ \ \ OR \ \ \ \ \ x+12 = 0\\\\x= 8 \ \ \ \ \ OR \ \ \ \ \ x=-12$

Since altitute can't be negative

x = 8

SO atitute is 8 cm

base is 12 cm