The base of isosceles triangle is 24 Chand it’s area is 192. Find its perimeter
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Base=24
Area=192
So, we can find the height,
Area=1/2*base*height
192 = 12H(height)
Height= 192/12
height = 16
Now, Height when we draw it will divide the base into two equal parts and it would be perpendicular to the base is the theorem.
So, we can calculate the two sides by pythagoras theorem. Both the sides are same so you need to calculate only once.
24/2= 12
12^2 + 16^2 = Side^2 (Pythagoras thorem)
144+256
400=side^2
side = 20
HOPE IT HELPS FRIEND!!
Area=192
So, we can find the height,
Area=1/2*base*height
192 = 12H(height)
Height= 192/12
height = 16
Now, Height when we draw it will divide the base into two equal parts and it would be perpendicular to the base is the theorem.
So, we can calculate the two sides by pythagoras theorem. Both the sides are same so you need to calculate only once.
24/2= 12
12^2 + 16^2 = Side^2 (Pythagoras thorem)
144+256
400=side^2
side = 20
HOPE IT HELPS FRIEND!!
mitu123456:
sorry I forgot to calculate perimeter.
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