Question

The base of lossless triangle is 12 cm and its perimeter is 32cm . Find its area

Answer 1

Here is your answer❤❤

Assuming the triangle is isosceles,

Base + Side + side = 32

12 + 2(side)= 32

2(side) = 20

Side = 10 cm

$area \: = \: \sqrt{s(s - a)(s - b)(s -c )}$

s = 16

$area \: = \: \sqrt{16(16 - 10)(16 - 10)(16 -12)}$

$area \: = \: \sqrt{16(6)(6)(4)}$

$area \: = \: \sqrt{2304}$

$area \: = \: 48 \: {cm}^{2}$

Hope it helps!!

Mark as brainlist!!