The base of the isosceles triangle measures 24 cm and its area is 60 sq .cm .Find its perimeter
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Let the altitude in the isosceles triangle=h
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Area of triangle=1/2×b×h
60 =1/2×24×h
60=12×h
h=60/12
h=5 cm
By Pythagoras theorem
Hypotenuse square=Side1 square+Side2 square
Isosceles side=12 square(as the height divides
base into 2 parts.)+5 square
=144+25
=169
Hypotenuse=13 cm
As it is an isoceles triangle its sides are equal.
Perimeter=13+13+24
50 cm
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