Question

the base of the parallelogram if one third of its height if the area of the parallelogram is 147 CM square find the base and height​

Answer 1

Answer:

area of a parallelogram = base ×height (b×h)

height =X

base=X/3

area=X×X/3(since, area =base ×height)

=X^2/3=147

X^2=147×3

X^2=441

X=21cm(since 21 squared =441)

Answer 2

The height of parallelogram is "21 cm" and base is "7 cm".

Step-by-step explanation:

$Let \ the \ height \ of \ a \ parallelogram \ be \ "x".\\The \ base \ be \ "\frac{1}{3}x"\\Area,A=147 \ cm^2\\\\As \ we \ know,\\\\The \ Area \ of \ parallelogram,\\A=base\times height\\\\On \ putting \ the \ values \ in \ the \ above \ expression,we \ get\\\\147=\frac{1}{3}x\times x\\ \\441=x^2\\\\x=\sqrt{441}\\ \\x=21\\\\Now,\\The \ height=21 \ cm\\The \ base=\frac{1}{3}\times 21=7 \ cm$

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