The base of the triangle is 5 cm longer than its altitude if the area of the triangle is 42 cm² what’s the altitude
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The base of a triangle is 4 cm longer than its altitude. If the area of the triangle is 48 sq. cm, then find its base and altitude.
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Base of a triangle is 4 cm longer than its altitude.Area of triangle = 48 cm^2 Let base of triangle = b Altitude = b - 4 Area = 12 × b × h = 48 12 × b × (b - 4) = 48 b^2 - 4b - 96 = 0 (b - 12)(b + 8) = 0 But, base cannot be negativeSo, base = 12 cm Altitude = 12 - 4 = 8 cm .
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