the base of triangular field is three times its altitude. if the cost of sowing the field at Rs.58 per hectare is Rs. 783, find its base and altitude
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Answered by
41
Let the Altitude be a
Base = 3a
We know that,
Area = Cost / Rate
=> 1/2 × Base × Altitude = 783 / 58 hectares
=> 1/2 × a × 3a = 13.5 hectares
=> 3a^2 = 27 hectares
=> a^2 = 9 hectares
=> a^2 = 9 × 10000 m^2
=> a = 300 m
Base of triangle = 300 m
Altitude of triangle = 900 m
Base = 3a
We know that,
Area = Cost / Rate
=> 1/2 × Base × Altitude = 783 / 58 hectares
=> 1/2 × a × 3a = 13.5 hectares
=> 3a^2 = 27 hectares
=> a^2 = 9 hectares
=> a^2 = 9 × 10000 m^2
=> a = 300 m
Base of triangle = 300 m
Altitude of triangle = 900 m
Answered by
9
Let the Altitude be a
Base = 3a
We know that,
Area = Cost / Rate
=> 1/2 × Base × Altitude = 783 / 58 hectares
=> 1/2 × a × 3a = 13.5 hectares
=> 3a^2 = 27 hectares
=> a^2 = 9 hectares
=> a^2 = 9 × 10000 m^2
=> a = 300 m
Base of triangle = 300 m
Altitude of triangle = 900 m
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