Question

The base QR of an equilateral tr iangle QPR lies on x axis.The co-ordinates of Q are (-4,0) and the origin is the mid point of base. Find the coordinates of point P&Q

Answer 1

By midpoint formula
X-axis
0=[(-4)+x]/2
x=4
Y axis
0=[0+y] /2
y=0

Answer 2

Answer:

here we have

using section formula

coordinates of R=(4,0)

now using distance formula we have PQ=PR

we getP=(0,y)

again we have PQ=QR

using dist formula we get y coordinate as √48

coordinates of P=(0,√48)

Hope it help you