Question

the base radii of the two cones are the same but the volumes are 44 pi metre cube and 95 metre cube respectively the ratio of the heights is. Please answer urgently​

Answer 1

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Answer 2

Step-by-step explanation:

Let there be cone 1 and cone 2 respectively.

Let the r and R be the radii of the two right circular cones respectively.

Ratio of base radii = 3 : 5

Volume of cone = 1/3πr²h

⇒Volume of cone 1/Volume of cone 2

⇒ (1/3*πr²h)/(1/3πR²h)

⇒ (1/3*π*3²*h)/(1/3*π*5²*h)

= 3²/5²

= 9/25

= 9 : 25

So, the ratio of their volumes is 9 : 25

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Let the volume two cones be v1 & v2 & r1 and r2 be the radii of the two right circular cones & height of the two cones be h.

Ratio of base radii = r1:r2= 3 : 5

Volume of cone = 1/3πr²h

Volume of first cone (v1)1/Volume of second cone (v2)

=(1/3×π×r1²×h)/(1/3×π×r2²×h)

= (1/3×π×3²×h)/(1/3×π×5²×h)

= r1²/r2²

= 3²/5²

= 9/25

= 9 : 25

Hence, the ratio of their volumes is 9 : 25

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