Question

- The base-radius and height of a cylinder
are 5 cm and 10 cm respectively. Then.
TSA is:
(a) 150 pi r cm²
(b) 300 cm²
(c) 150 cm²
(d) 300 cm²​

Answer 1

$\boxed{\huge{\bf{\star{Correct\:question \:-:}}}}$

• The base-radius and height of a cylinder are 5 cm and 10 cm respectively. Then , Find Total Surface Area.

AnswEr-:

• $\underline{\boxed{\star{\sf{\blue{ The\:option\:A\:or\:150\pi cm^{2} \:is\:Correct. }}}}}$

• $\underline{\boxed{\star{\sf{\blue{ The\:option\:A\:or\:150\pi cm^{2} \:is\:Correct. }}}}}$

EXPLANATION-:

• $\frak{Given \:\: -:} \begin{cases} \sf{The\:base-radius\:of\:Cylinder \:\:is\:= \frak{5cm}} & \\\\ \sf{Height \:of\:Cylinder \:is \:=\:\frak{10cm}}\end{cases}$

• $\frak{To \:Find\: -:} \begin{cases} \sf{The\:Total \:Surface \:Area\:of\:Cylinder \:}\end{cases}$

$\dag{\sf{\large { Solution-:\:}}}$

• $\underline{\boxed{\star{\sf{\blue{ Total\:Surface\:Area_{(Cylinder)}  \: = \: 2 \pi \times Radius( Height +Radius)}}}}}$

• $\frak{Here \:\: -:} \begin{cases} \sf{The\:base-radius\:of\:Cylinder \:\:is\:= \frak{5cm}} & \\\\ \sf{Height \:of\:Cylinder \:is \:=\:\frak{10cm}}& \\\\ \sf{\pi =\dfrac{22}{7}}\end{cases}$

$\dag{\sf{\large { Now-:\:}}}$

• $\implies{\sf{\large { \:\:\: 2 \times \pi \times 5 \: (10+5)\: }}}$

• $\implies{\sf{\large { \:\:\: 2 \times \pi \times 5 \: (15)\: }}}$

• $\implies{\sf{\large { \:\:\: 2 \times \pi \times 75\: }}}$

• $\implies{\sf{\large { \:\:\: 2 \times 75 \times \pi \: (10+5)\: }}}$

• $\implies{\sf{\large { \:\:\: 150 \times \pi cm^{2}}}}$

• $\dag{\sf{\large { Or,\:}}}$

• $\implies{\sf{\large { \:\:\: 150\pi cm^{2} }}}$

$\dag{\sf{\large { Therefore-:\:}}}$

• $\underline{\boxed{\star{\sf{\blue{ Total\:Surface\:Area_{(Cylinder)}  \: = \:150\pi cm^{2} }}}}}$

$\dag{\sf{\large { Hence:\:}}}$

• $\underline{\boxed{\star{\sf{\blue{ Total\:Surface\:Area_{(Cylinder)}  \: = \:150\pi cm^{2} }}}}}$

• $\underline{\boxed{\star{\sf{\blue{ The\:option\:A\:or\:150\pi cm^{2} \:is\:Correct. }}}}}$

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