Question

the base radius and height of a right circular cylinder are 7cm and 3. 5cm the volume of cylinder is
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Answer 1

Given :

• Radius of Cylinder = 7cm.
• Height of Cylinder = 3.5cm.

To Find :

• Volume of Cylinder.

Solution :

$\longmapsto\tt{Radius=7cm}$

$\longmapsto\tt{Height=3.5cm}$

Using Formula :

$\longmapsto\tt\boxed{Volume\:of\:Cylinder=\pi{{r}^{2}h}}$

Putting Values :

$\longmapsto\tt{\dfrac{22}{\cancel{7}}\times{\cancel{7}}\times{7}\times\dfrac{35}{10}}$

$\longmapsto\tt{\dfrac{5390}{10}}$

$\longmapsto\tt\bold{539.0{cm}^{3}}$

So , The Volume of Cylinder is 539cm³...

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• C.S.A of Cylinder = 2πrh
• T.S.A of Cylinder = 2πr(r+h)
• Volume of Cylinder = πr²h

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Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow BASE\:RADIUS\:OF\:A\:CYLINDER\:IS\:7cm$

$\sf\dashrightarrow HEIGHT\:OF\:CYLINDER\:IS\:3.5cm$

$\sf\dashrightarrow \pi= \dfrac{22}{7}$

$\large\underline\bold{TO\:FIND,}$

$\sf\large\dashrightarrow VOLUME\:OF\:CYLINDER.$

✯.FORMULA IN USE,

$\large{\boxed{\bf{ \star\:\: VOLUME\:OF\:CYLINDER= \pi r^2h\:\: \star}}}$

$\large\underline\bold{SOLUTION,}$

$\sf\therefore VOLUME\:OF\:CYLINDER= \pi r^2h$

$\sf\implies \dfrac{22}{7} \times (7)^2 \times (3.5)$

$\sf\implies \dfrac{22}{\cancel{7}} \times \cancel{(7)} \times (7)\times (3.5)$

$\sf\implies 22 \times 7 \times (3.5)$

$\sf\implies 22 \times 24.5$

$\sf\implies 539cm^3$

$\large{\boxed{\bf{ \star\:\: volume\:of\:cylinder\:= 539cm^3\:\: \star}}}$

$\large\underline\bold{VOLUME\:OF\:CYLINDER\:IS\:539cm^3}$

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