Question

The base sides of two triangles of equal altitudes of 15 cm and 12cm .the area of the first triangle is 315cm2 What is the area of the second triangle

Answer 1

Answer:

Step-by-step explanation:

area of 1st triangle = 1/2 × b × h

          315 cm^2     = 1/2 × 15 cm × h

   315 cm^2  × 2/1  = 15h

       630 cm^2      = 15h

  630 cm^2 / 15     = h

                42 cm    = h

they have mentioned that the both triangles have equal altitudes so height of 2nd triangle = 42 cm

area of 2nd triangle = 1/2 × b × h      

                                 =  1/2 × 12 cm × 42 cm

                                 = 6 cm × 42 cm

                                 = 252 cm^2

therefore the area of 2nd triangle is 252 cm^2

this is the correct answer

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