Question

the battery of a pocket calculator supplies 0.35A at a p.d of 6V . What is the power rating of the Calculator​

Answer 1

Explanation:

P = V I

P = 6x0.35

P = 2.10 watt

Answer 2

Answer:

The Power Rating of the calculator is 2.1W

Explanation:

Given that,

The battery of a pocket calculator supplies 0.35A of current at a potential difference of 6V.

The current supplied by battery=0.35A

$= > i=0.35A$

The potential difference at which the current is supplied is 6V

$V = 6V$

We are required to find the power rating of the calculator.Power rating is nothing but power of the battery.It is mathematically equivalent to the product of Current flowing in thr battery amd the potential difference of the battery.Therefore,mathematically we can write-

$P=Vi$

Substituting the calues if voltage and current in the above relation,we get

$P = 6 \times 0.35 = 2.1W$

Therefore,the power rating of the calculator us foind to be 2.1W

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