The batting average for 40 innings of a cricketer is 50 runs. his highest score exceeds his lowest score by 172 runs. if these two innings are excluded, the average of the remaining 38 innings is 48 runs. the highest score of the player is:
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Answered by
19
Here,
Total runs scored by cricketer = 50*40 = 2000.
Let highest score be x.
lowest score = (x-172) run
Now, As per the question ,
2000-(x+x-172)= 38*48
i.e. x= 174.
Hence, Highest score of the player is 174 runs.
Total runs scored by cricketer = 50*40 = 2000.
Let highest score be x.
lowest score = (x-172) run
Now, As per the question ,
2000-(x+x-172)= 38*48
i.e. x= 174.
Hence, Highest score of the player is 174 runs.
Answered by
3
Answer:
174
Step-by-step explanation:
Let the lowest score in one innings be x.
Then, highest score in an innings = x + 172
Total runs in 40 innings = 40 x 50 = 2000
Total runs in 38 innings = 38 x 48 = 1824
Given, 2000 - {x + (x + 172)} = 1824
⇒ 1828 - 2x = 1824
⇒ 2x = 4
⇒ x = 2
∴ Highest score = 172 + 2 = 174
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