Physics, asked by lephongkonyak92, 11 days ago

The beta -decay of F²⁰ leave the product nucleus Nè²⁰ in an excited state of energy 1.63Mev.Find out the energy and frequency of r-ray emitted in the process.Given h=6.6×10‐³⁴js,1ev=1.6×10‐¹⁹j.​

Answers

Answered by skneha783
0

Answer:

192e is the answer

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jekkdkellrkrkrk

Explanation:

bhiihyh

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