Question

The binding energy of an electron in the ground state of the He atom is equal to 24 eV. The energy required to remove both the electrons from the atom will be

Answer 1

On removing electron from helium atom becomes single electron atom

So applying Bohrs model energy of single electron is given by

-13.6× ( Z^2/ n^2 )

where Z is atomic no.

n is no. Of she'll in which electron is present

Therefore ,

Energy comes out to be -13.6 × ( 4 / 1 ) = -54.4

Therefore ,

Total energy to remove both the electron is

24.6 + 54.4 = 79

Answer 2

Answer:

On removing electron from helium atom becomes single electron atom

So applying Bohrs model energy of single electron is given by

-13.6× ( Z^2/ n^2 )

where Z is atomic no.

n is no. Of she'll in which electron is present

Therefore ,

Energy comes out to be -13.6 × ( 4 / 1 ) = -54.4

Therefore ,

Total energy to remove both the electron is

24.6 + 54.4 = 79