Chemistry, asked by johnny23316, 10 months ago

The binding energy of the electron in the lowest orbit of the hydrogen atom is 13.6 eV. The energies required in electronvolt to remove an electron from three lowest orbits of the hydrogen atom are. a) 13.6 , 6.8 , 8.4 eV. b) 13.6 , 10.2 , 3.4 eV. c) 13.6 , 27.2 , 40.8 eV. d) 13.6 , 3.4 , 1.5 eV​

Answers

Answered by Gajoh
3

E = 13.6 z^2/n^2

E1 = 13.6 x 1/(1)^2 = 13.6

E2 = 13.6 x (1)^2/(2)^2

13.6/4 = 3.4

E3 = 13.6 x (1)^2/(3)^2

= 13.6/9

= 1.51

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