Question

The binding energy per nucleon of 10x is 9 mev and that of 11x is 7.5 mev where x represents an element. The minimum energy required to remove a neutron from 11x is

Answer 1

Answer:

The nuclear reaction is represented as follow:

O817 → O816 + n01

B.E per nucleon of O816 = 7.97 MeV

B.E per nucleon of O17 = 7.75 MeV

Energy required to remove a neutron from O817 = ?

If mp represents the mass of a proton and mn that of a neutron, the energy required to remove a neutron from O817 is given by,

E = energy equivalent of (mass of O816 + mn - mass of O817)

= (8 mp + 8 mn- 7.97 ×16) + mn - (8mp+9mn - 7.75 × 17)

=[7.75×17-7.97×16] MeV = 4.23 MeV.