Question

The capacity of a parallel plate condenser is 5f. When a glass plate is placed between the plates of the conductor, its potential becomes 1/8thof the original value. The value of dielectric constant will be

Answer 1

Hey Dear,

◆ Answer -

k = 8

◆ Explanation -

# Given -

C = 5 μF

V' = V/8

# Solution -

Initially, capacitance of the condenser is given by -

C = Q/V

Later, capacitance of the condenser is changed to -

C' = k.C

But we know C' = Q/V', thus -

Q/V' = k × Q/V

k = V/V'

k = V / (V/8)

k = 8

Therefore, dielectric constant of the material is 8.

Thankz for asking...