Question

THE BISECTORS OF ANGLE BAC AND ANGLE ABC MEET AT A POINT O. IF ANGLE BCA=62 DEGREE. FIND ANGLE AOB.

Answer 1

Answer:

AOB=70 DEGREE

Step-by-step explanation:

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Answer 2

Answer: 121°

Step-by-step explanation:

∠BAC + ∠ABC + ∠BCA = 180o

=> ∠BAC + ∠ABC = 180o - 62o = 118o

Dividing by 1/2

$\frac{1}{2}$  x ∠BAC + $\frac{1}{2}$  x ∠ABC= $\frac{1}{2}$  x 118°

∠BAO + ∠ABO = 59°

Now in Triangle ABO

∠BAO + ∠ABO + ∠AOB= 180°

=> 59o + ∠AOB = 180°

=> ∠AOB = 180°- 59° = 121°