the block A and B are arranged
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normal reaction due to blockA=10×10=100
force of friction=100×0.20=20
now to accelerate blockA we have to overcome the force of friction i.e.20N
so minimum force=20N
so weight of blockB=20÷10=2kg
force of friction=100×0.20=20
now to accelerate blockA we have to overcome the force of friction i.e.20N
so minimum force=20N
so weight of blockB=20÷10=2kg
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Hope this helps
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