Question

The block is placed on frictionless surface in gravity free space. A heavy string of a mass m is connected and force F is applied on the string, then the tension at the middle of Ć rope is u m M​

Answer 1

Answer:

Correct option is

A

m+M

(

2

m

+M)F

The tension at any point on the rope is basically what force acts on the remaining part.

Due to force F, the whole system would move with an acceleration of a=

M+m

F

At the midpoint of the rope the tension should be equal to the value of the force which would be able to pull the left part of the rope and the block with acceleration a.

∴T=(M+

2

m

)

M+m

F

Explanation:

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