Question

The block of mass 1000 kg lying steady on the horizontal surface of a table needs 200 N horizontal force to come into motion. What is the coefficient of static friction between the block and the surface of table? [take g = 10 m/s²]
(A) 0.2
(B) 0.02
(C) 0.5
(D) 0.05

Answer 1

0.5is the correct answer

Answer 2

Answer:

ans is B 0.02

Explanation:

Frictional force =amumg

200=10000amu

amu =0.02