the measure of an angle is 40°more the measure of its complement. find its measure 70°, less than its supplement.
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Solution:Let the angle be 'x'
Therefore,supplement=180°-×
complement=90°-x
A/Q
x=90°-x+x=40°
x=90°=40°
x=90°-40°
x=50°
Also,
A/Q
x=180°-x-x=70°
x=180°-2x=70°
x= -2x=70°-180°
-2x+x=-110°
-x=-110°
x=110°
Therefore,supplement=180°-×
complement=90°-x
A/Q
x=90°-x+x=40°
x=90°=40°
x=90°-40°
x=50°
Also,
A/Q
x=180°-x-x=70°
x=180°-2x=70°
x= -2x=70°-180°
-2x+x=-110°
-x=-110°
x=110°
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