The bob of a simple pendulum of length 1 m has mass 100g and a speed of 1.4 m/s at the lowest point in its path. Find the tension in the string at this moment. Take g=9.8m/sec2
Answers
Answered by
146
At lowest point, two forces are acting on the bob
a) Tension in string upwards
b) mg downwards.
As it is moving along circular path hence
T−mg=mv2rT−mg=mv2r
=> T=mg+mv2rT=mg+mv2r
Given mm = 100g = 0.1 Kg, vv= 1.4 m/s, rr= ll= 1 m, g=10m/s2g=10m/s2
Hence T = 1.196 N
Hope you are satisfied.....
Have a good day......
Don't forget to mark it the brainliest.....
Regards......
RJ Nicole Tyler
a) Tension in string upwards
b) mg downwards.
As it is moving along circular path hence
T−mg=mv2rT−mg=mv2r
=> T=mg+mv2rT=mg+mv2r
Given mm = 100g = 0.1 Kg, vv= 1.4 m/s, rr= ll= 1 m, g=10m/s2g=10m/s2
Hence T = 1.196 N
Hope you are satisfied.....
Have a good day......
Don't forget to mark it the brainliest.....
Regards......
RJ Nicole Tyler
ehbdhjxhknh:
can we write the formula of, t=mv²/r+mg
Answered by
24
Answer:
Explanation:
I hope it will be helpful to you.
Attachments:
Similar questions