Question

The body is projected at an angle 60 degree with horizontal with kinetic energy k when the velocity make an angle 30 degree what is kinetic energy of body will be

Answer 1

let, the initial velocity is u and at point P the velocity becomes v when it makes an angle 30°.

at point P,

$u \cos(60) = v \cos(30)$

or,

$v = \frac{u}{ \sqrt{3} }$

initially ,

$k= \frac{1}{2} m {u}^{2}$

at that point the kinetic energy is,

$\frac{1}{2}m {v}^{2} = \frac{1}{2} m \frac{ {u}^{2} }{3}$

$\: \: \: \: \: \: \: = \frac{k}{3}$

Answer 2

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Explanation: