Question

the boiling point and freezing point of water are 100°C and 0°C respectively convert these temperature in k.

Answer 1

t(k)=t(c) +273. t(k)=100+273=373k similarly, t(k)=t(c) +273 t(k)=0 +273=273k

Answer 2

boiling point = k = 273+°c
= k= 273+0 = 273k

melting or freezing point = k= 273+°c
= k= 273+100= 373k