The boiling point of 0.2 mol kg⁻¹ solution of X in water is
greater than equimolal solution of Y in water. Which one of
the following statements is true in this case ? [2015]
(a) Molecular mass of X is greater than the molecular mass
of Y.
(b) Molecular mass of X is less than the molecular mass of
Y.
(c) Y is undergoing dissociation in water while X undergoes
no change.
(d) X is undergoing dissociation in water.
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Answer:
(a) is the answer
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The boiling point of 0.2 mol kg⁻¹ solution of X in water is greater than equimolal solution of Y in water. X is undergoing dissociation in water.
- Option (d) is correct.
- we know that,
- molarity = moles of solute / mass of solution
- and
- given, molarity of X = 0.2 mol kg⁻¹ = molarity of Y
- given, ΔTb (X) > ΔTb (Y)
- where ΔTb = elevation in boiling point.
- we have,
- ΔTb =Kb m
- where,
- m = molality of the solution
- Kb = molal boiling point constant
- as ΔTb∝i
- where, i = vant Hoff factor
- we have,
- iΔTb =iKb m
- as ΔTb (X) > ΔTb (Y)
- ⇒ i(X) > i(Y)
- hence, X is undergoing dissociation in water.
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