Question

The boiling point of a solution containing 0.20g of a substance X in 20.00g of ether is 0.17k higher than that of pure ether calculate the molecular mass of solute kb=2.16kkmol

Answer 1

Answer:

Given:

∆Tb = 0.17

mass of substance x = 0.20 gm

mass of solvent = 20 gm

kb for ether= 2.16

∆Tb = kb× m

0.17 = 2.16 × 0.20 × 1000/ M × 20

M= 124.44