the boiling point of alcohol is 78 degree Celsius what is the temperature on Kelvin scale
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Answered by
15
Solution:
Boiling point of the given alcohol = 78°C
Kelvin scale temperature = Celsius scale temperature + 273
Kelvin scale Temperature = 78 + 273
= 351 K
Hence, temperature of 78°C on Celsius scale is equal to 351 K on the Kelvin scale.
Kelvin scale of temperature is invented by “Lord William Thomson Kelvin”. It is used only for research work by the scientist. For measuring temperature, Kelvin is the SI unit. K is the symbol used for representing Kelvin. Kelvin scale and Celsius scale of temperature has a relationship and is written as,
Temperature on Kelvin scale = Temperature on Celsius scale + 273
=315k
Answered by
3
Answer:
Given temperature of alcohol= 78°C
78° C =351.15 K [on Kelvin scale]
by the given formula=
78° C +273.15 = 351.15 K
[celcius scale temperature + 273= Kelvin scale temperature]
hope it's helpful
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