Question

the boiling point of ethane is -88 degree Celsius. This temperature will be equivalent to​

Answer 1

Solution :-

Given that boiling point of ethane is -88 °C .

This temperature can be converted into Farenheit and Kelvin . So , we know a relation between them as ,

$\boxed{\red{\bf \qquad\green{\dag} \:\dfrac{C}{5}=\dfrac{F-32}{9}=\dfrac{ K - 273}{5}\qquad}}$

Relate each of them with one another once ,

$\small \blue{\bf\mapsto Celsius\:to\: Farenheit:-}$

$\tt:\implies \dfrac{C}{5}=\dfrac{F-32}{9}$

$\tt:\implies \dfrac{-88}{5}=\dfrac{F-32}{9}$

$\tt:\implies F-32 = \bigg\lgroup 9\times \dfrac{-88}{5}\bigg\rgroup$

$\tt:\implies F - 32 = -158.4$

$\tt:\implies F = -158.4+32$

$\underline{\boxed{\red{\tt{\longmapsto \: Farenheit\:=\:(-126.4)^{\circ}F }}}}$

$\rule{200}2$

$\small\blue{\bf \mapsto Celsius\:to\: Kelvin:-}$

$\tt:\implies C = K - 273$

$\tt:\implies -88= K - 273$

$\tt:\implies K = 273 - 88$

$\underline{\boxed{\red{\tt{\longmapsto \: Farenheit\:=\:185K }}}}$

$\boxed{\green{\sf \pink{\dag} Hence\: temperature\:in\:Farenheit\:is\:-126.4^{\circ}F}}$

$\boxed{\green{\sf \pink{\dag} Hence\: temperature\:in\:Kelvin\:is\:185K}}$