Science, asked by razzz1, 1 year ago

the boiling point of water at 735 torr in 99.07 celsius. the mass of nacl added in 100 g of water to make its boiling point 100 is (Kb=0.51)

Answers

Answered by aqibkincsem
76
The difference of the new and the present boiling points is 100 – 99.07 = 0.93 degree Celsius.


The molality of NACL in the water can be calculated by the formula ½ (0.93 / 0.51) mol kg -1.

From it, the mass of the added NACL is calculated by applying a specific formula that says – ½ x 1/10 x (0.93/0.51) x 58.5 = 5.33 gm. Thus, the total amount of NACL to be added is calculated as 5.33 gm.

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