find the value of p,for whichone root of the quadratic equation px^2-14x+8=0 is 6 times the other
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let the roots of equation
Px² -14x + 8 = 0 is ß and 6ß
sum of roots = -( -14)/P
ß + 6ß = 14/P
7ß = 14/P
ß = 2/P ------(1)
product of roots = 8/P
ß × 6ß = 8/P
6ß² = 8/P
put equation (1) in here
6( 2/P)² = 8/P
24/P² = 8/P
3/P = 1
P = 3
Px² -14x + 8 = 0 is ß and 6ß
sum of roots = -( -14)/P
ß + 6ß = 14/P
7ß = 14/P
ß = 2/P ------(1)
product of roots = 8/P
ß × 6ß = 8/P
6ß² = 8/P
put equation (1) in here
6( 2/P)² = 8/P
24/P² = 8/P
3/P = 1
P = 3
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