The boiling point of water becomes 100.52'c if 1.5 g of a nonvolatile solute is dissolved in 100 ml of it. Calculate the molecular mass of the solute (Kb for water =0.6 kmol-l)
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The molecular mass of the solute is 17.3 g.mol⁻¹
Explanation:
The elevation in boiling point is given by the formula:
ΔT = Kb × M
Where,
Kb = Dissociation constant
M = Molality of the solute
On substituting the values, we get,
100.52 - 100 = 0.6 × (1.5/M)/(100/1000)
0.52 = 0.6 × (1.5/M × 1000/100)
0.52 = 0.6 × 15/M
0.52 = 9/M
M = 9/0.52
∴ M = 17.30 g.mol⁻¹
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