Chemistry, asked by rajarajan2877, 6 months ago

The boiling points of ethyl acetate and CH3OH,
respectively, are 77°C and 65°C. Which of the
following reactions can be shifted to the right by the
distillation of the reaction mixture at about 66°C
I) MeCOOEt + MeOH →
II) MeCOoMe+ EtOH →
III) MeCOOMe+ PhOH →
IV) MeCOOPh+MeOH →​

Answers

Answered by Anonymous
3

Answer:

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Attachments:
Answered by faiz58950
0

Answer:

(I),(II)

(II),(III)

(I),(III)

(II),(IV)

Answer :

D

Solution :

In (II), the product are ethyl acetate (boiling point 77∘C) and MeOH(boiling point 65∘C). Thus at 66∘C, MeOH is removed due to distillation and equilibrium is shifted to R.H.S.

In (IV), phenyl acetate is more reactove than methyl acetate.

Explanation:

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