The bond angle between two hybrid orbitals is 105°. The percentage of s-character of hybrid orbital is between
(a) 50 - 55%
(b) 9 - 12%
(c) 22 - 23%
(d) 11 - 12%
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Answer:
The percentage of s-character of hybrid orbital is between option (c) 22 - 23%
Explanation:
s-character of hybrid orbital is directly proportional to the bond angle.
The percentage of s-character of hybrid orbital is given by the relation :
s/s-1 = cosФ
where,
s = s-character
Ф = bond angle
so,
s/s-1 = cos 105°
=> s/s-1 = -0.26
=> s = 0.26 - 0.26s
=> 1.26s = 0.26
=> s = 0.26/1.26
=> s = 0.2 = 20%
Hence the most appropriate choice will be option (c) 22 - 23%
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Answer:
thank you for your answer it was very helpful to me
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