Chemistry, asked by chayat7854, 1 year ago

The bond angle between two hybrid orbitals is 105°. The percentage of s-character of hybrid orbital is between
(a) 50 - 55%
(b) 9 - 12%
(c) 22 - 23%
(d) 11 - 12%

Answers

Answered by shubhamjoshi033
11

Answer:

The percentage of s-character of hybrid orbital is between option (c) 22 - 23%

Explanation:

s-character of hybrid orbital is directly proportional to the bond angle.

The percentage of s-character of hybrid orbital is given by the relation :

s/s-1 = cosФ

where,

s = s-character

Ф = bond angle

so,

s/s-1 = cos 105°

=> s/s-1 = -0.26

=> s = 0.26 - 0.26s

=> 1.26s = 0.26

=> s = 0.26/1.26

=> s = 0.2 = 20%

Hence the most appropriate choice will be option (c) 22 - 23%

Answered by baskaushal
0

Answer:

thank you for your answer it was very helpful to me

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