Question

The trigonal bipyramidal geometry is obtained from the hybridisation :
(a) dsp³ or sp³d
(b) dsp² or sp²d
(c) d²sp³ or sp³d²
(d) None of these

Answer 1

a is the correct option ...........
eg Pcl5
in which two bond are of 90 degree and there are of 60 degree ( triangular in shape)

Answer 2

Answer: The correct answer is Option a.

Explanation:

To calculate the hybridization of a compound, we use the equation:

$\text{Number of electrons}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

For obtaining trigonal bipyramidal geometry, we require 5 electron pairs and that is obtained from $sdp^3\text{ or }sp^3d$ hybridization around the central metal atom.

Former hybridization requires inner d-orbitals and later one requires outer d-orbital.

Hence, the correct answer is Option a.