Question

the bond dissociation energy of hydrogen bonds in water molecule is how much? ​

Answer 1

Answer:

Explanation:

The bond dissociation energy is an endothermic process and it is the energy required to break a bond and form two atomic or molecular fragments, each with one electron of the originally shared pair.  

Now, the bond dissociation energy of hydrogen bonds in a water molecule is:

In a water molecule, the dissociation of HO-H bond requires 118.8 kcal/mol (497.1 kJ/mol) and the remaining hydroxyl radical requires 101.8 kcal/mol (425.9 kJ/mol) for dissociation. The covalent O–H bonds in water consist of 110.3 kcal/mol (461.5 kJ/mol) of bond energy which is the average of these values.

Answer 2

Explanation:

The bond dissociation energy is the measure of  the strength of a chemical bond A-B.

The dissociation of HO–H bond of a water molecule (H2O) requires 118.8 kcal/mol (497.1 kJ/mol) and the dissociation of the remaining OH radical requires 101.8 kcal/mol (425.9 kJ/mol). The bond energy of the covalent O–H bonds in water is the average of the these two values:

Bond Energy of the covalent O-H bonds in H2O = {(118.8+101.8)kcal/mol}/2

which is equal to 110.3 kcal/mol (461.5 kJ/mol)