Question

The bond energy of f2 is 150 kilo joule per mole the minimum frequency of a photon to break this bond

Answer 1

Answer:

Explanation:

Given The bond energy of f2 is 150 kilo joule per mole the minimum frequency of a photon to break this bond

Now we need to convert kJ / mol to J

So energy in joule = 150 KJ/mol x 1000 J /1 KJ x 1 mol / 6.022 x 10^23 photon

E = 2.49 x 10^- 19 J

Now to find the frequency of the photon we have

E = hν  

ν = E / h

  = 2.64 x 10^-19 J / 6.626 x 10^-34 J . s

  = 0.375 x 10 ^15 s^-1

 = 3.75 x 10^14 s^-1

So the frequency of the photon will be 3.75 x 10^14 s^-1