Question

The bottom of a cylindrical vessel has a circlular hole of radius r and at a depth h below the water level. If the diameter of the vessel is D, the find then speed with which the water level in the vessel drops.
( consider r<< D)​

Answer 1

[Q]__?

The velocity of efflux = √2gh

The rate of the flow of the liquid out of the

hole = Av

= πr^2 √2gh

By using equation of continuity

(Av)container = (Av)hole

π [D^2 /4]v = πr^2 √2gh

v = 4r^2/D^2 √2gh

∴ Speed with which water level falls

= 4r^2/D^2 √2gh.

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Answer 2

Answer:

A large vessel with a small hole at the bottom is filled with water and kerosene