Question

The brackes applied to car produce an acceleration of 6m/s2 in the opposite direction to the motion . If the cars takes 2s to stop after the applicition of brackes ,calculate thecdistance it travel during this time..????

Answer 1

Answer:

s=12m

Explanation:

Acceleration a = -6 m/s^2

Time t = 2 s

Final velocity v = 0 m/s

Let initial velocity be u

Let distance be s

v = u + at

So, 0 = u + (-6)(2)

So, u = 12 m/s

Now, s = ut + (1/2) at^2

So, s = 12(2) + (1/2)(-6)(2^2)

So, s = 24 - 12

So, s = 12 m