Question

The brake applied to a running train produce an acceleration of 0.6 msquare in the direction opposite of that to if train takes 1min. Calculate the distance traveled by it in this time

Answer 1

$<marquee> Answer </marquee>$

$\star \: \blue{ \rm{Given}}$

acceleration = 0.6 m/s^2

time = 1min = 60s

$\star \: \rm{ \blue{ To \: Find}}$

distance travelled by train

$\star \: \rm{ \blue{Formula}}$

As per kinematics equations...

$\dagger \: \underline{ \boxed{ \mathfrak{ \orange{v = u + at}}}} \\ \\ \dagger \: \underline{ \boxed{ \mathfrak{ \pink{ {v}^{2} - {u}^{2} = 2aS}}}} \\ \\ \star \: \rm{ \blue{Calculation}} \\ \\ \mapsto \rm \: v = u + at \\ \\ \mapsto \rm \: u = at = 0.6 \times 60 = 36 \: \frac{m}{s} ( \because \: v = 0) \\ \\ \leadsto \rm \: {v}^{2} - {u}^{2} = 2aS \\ \\ \leadsto \rm \: s = \sqrt{ \frac{ {u}^{2} }{2a} } = \sqrt{ \frac{( {36})^{2} }{2 \times 0.6} } = \sqrt{ \frac{1296}{1.2} } = \sqrt{1080} \\ \\ \underline{ \boxed{ \mathfrak{ \orange{S = 32.86 \: m}}}} \: \red{ \star}$