Question

The brakes appilied to a car produce a uniform retardation of 0.5 m/s² the car covers a distance of 16 m before stopping how were the brakes appilied

Answer 1

$a = - 0.5ms^{ - 2} \\ s = 16m \\ v = 0 \\ using \: {v}^{2} - {u}^{2} = 2as \\ {(0)}^{2} - {u}^{2} = 2( - 0.5)(16) \\ - {u}^{2} = - (16) \\ u = 4m {s}^{ - 1}$
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