Question

The brakes applied ro a car produce an acceleration of 6 M/Ss in the opposite direction to the motion. If the car takes 2 seconds to stop the car after the the application of brakes , calculate the distance it travels durind this time

Answer 1

Hii..
Here is your answer..

Solution:-
Acceleration=(-6m/s^2)
Time =2 seconds
Final velocity=0
Initial velocity=?

By using equation,that is,
$= > v = u + at \\ = >u = v - at \\ = > u = 0 - ( - 6 \times 2) \\ = > u = 12$
Now,
We have to find Distance and we'll find it by using equation,that is,
$= > {v}^{2} = {u}^{2} + 2as \\ = > {(0)}^{2} = {(12)}^{2} + 2 \times ( - 6) \times s$
$= > 12s = 144 \\ = > s = \frac{144}{12} \\ = > s = 12$

Hence,
The distance he travelled =12m

Hope it helps uh....✌️✌️✌️