the brakes applied to a bus produce an acceleration of 4 m/s² in the opposite direction to the motion. If the bus takes 3 seconds to stop after the application of brakes, calculate the distance it travels during this time
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Answer:
1.5 metres
Explanation:
Given: a(acceleration)= 4m/s²
v(final velocity)= 0( as the bus stops)
t(time)= 3seconds
s(distance)= ?
Solution: we will have to find u i.e initial velocity
therefore, using v= u+ at
u= v-at
u= 0- 12
u= -12m/s
v²= u²+2as
v²-u²/2a= s
12/8= s
s= 12/8= 1.5metres
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