the brakes applied to a car acceleration on - 10 M per second square if the car takes 5 seconds stop after applying the brakes calculate the distance covered by the car before coming to the rest
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v=0
a=-10
t=5
v=u+at
0=u-10(5)
0=u-50
u=50
s=ut+1/2 at^2
s = 50×5+1÷2×−10×5×5=125m
a=-10
t=5
v=u+at
0=u-10(5)
0=u-50
u=50
s=ut+1/2 at^2
s = 50×5+1÷2×−10×5×5=125m
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